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5r^2-10r-60=6
We move all terms to the left:
5r^2-10r-60-(6)=0
We add all the numbers together, and all the variables
5r^2-10r-66=0
a = 5; b = -10; c = -66;
Δ = b2-4ac
Δ = -102-4·5·(-66)
Δ = 1420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1420}=\sqrt{4*355}=\sqrt{4}*\sqrt{355}=2\sqrt{355}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{355}}{2*5}=\frac{10-2\sqrt{355}}{10} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{355}}{2*5}=\frac{10+2\sqrt{355}}{10} $
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